PLZ HELP ......... The length of a rectangle is shown below: On a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis, two points A and B are shown. The point A is on ordered pair 1, 3, and the point B is on ordered pair negative 1, 3. A straight line joins the points A and B. If the area of the rectangle to be drawn is 10 square units, where should points C and D be located, if they lie vertically below the line that connects B and A, to make this rectangle? (5 points) C(−1, 1), D(1, 1) C(−1, −2), D(1, −2) C(−1, 5), D(1, 5) C(−1, −7), D(1, −7)

Answer:The point C is (-1 , -2) and point D is (1 , -2)Step-by-step explanation:* Lets study the information in the problem- ABCD is a rectangle# AB = CD , BC = AD# m∠A = m∠B = m∠C = m∠D = 90°- Point A is (1 , 3)- Point B is (-1 , 3)* That means AB is a horizontal segment because A and B have  the same y-coordinates- The length of AB = 1 - -1 = 2- The area of the rectangle is 10 units²∵ The area of the rectangle = L × w∵ AB is the width and = 2 units∴ L = 10 ÷ 2 = 5 units- Point C lies vertically below point B by 5 units- Point C has the same x-coordinate of point B∴ Point C is (-1 , 3 - 5) = (-1 , -2)- Point D lies vertically below point A by 5 units- Point D has the same x-coordinate of point A∴ Point C is (1 , 3 - 5) = (1 , -2)* The point C is (-1 , -2) and point D is (1 , -2)